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Comment on K3 by Chris Feige

semisemetric self orthagonol latin square for n=7

0 3 6 2 5 1 4
5 1 4 0 3 6 2
3 6 2 5 1 4 0
1 4 0 3 6 2 5
3 2 5 1 4 0 3
4 0 3 6 2 5 1
2 5 1 4 0 3 6


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