My instincts tell me that the morse code translation is a fragment of a larger solution, which means that something comes before it. So what I did was go back to look at it all again. There are 97 unsolved variables in K-4. If you add the keyword kryptos to that, it gives you 104 variables, which divided by 4 gives you four 26 variable strings which could be used as 26 variable rotors as the Germans did in World War II.
Given that my personality does not allow me to give up on an unsolved problem, here we are. I also know I am going against the grain in the Kryptos community by making these ideas public, when most, if not all, other folks keep their work to themselves in the hopes they will be the sole solver of the code.
To them I say there is no “I” in “team”.
So if one of my ideas leads to solving the code by someone else, that is exactly what I want to happen. See, i was crunching the equations in my mind a few months ago because I think in equations. It’s something I can’t explain. Anyway, I got to thinking that if there were 20,000 people working on this problem for X number of years, it may be the best option to let them win it. I say that because of the possibility that out of that 20,000 people, there may be 50 exceptional ones, and it would be to no one’s benefit to crush them. So even if you are exceptional, it is more beneficial for a group setting to universally figure something out than a single individual. Getting past the groupthink however is the most difficult challenge outside of the method of solving kryptos.
So Kryptosfan, did you check out the rotor positions and IP (not internet protocol but Initial Point) that I used? There are 10 variables of the first 10 variables of the 97 unsolved variables accounted for. The 10th is an “I”, but that is explainable in the quadrangle position “10″ which uses an up arrow. The “L” is from variable position 16 dropping down to position 6 using the distribution method of the Chutes and Ladders game.